To answer this question the voltage of the heater must be given. I = W/E.
106 amps
24 amps. This could be three 11.54 resistors connected in star, or three 34.6 ohm resistors connected in delta.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
23
There is one part of the question missing. To find an answer the kW of the heater must be stated. Then the equations used are, to change kW to watts, Kw/1000 = watts. Once that is found then use, I = W/E, Amps = Watts/Volts. This will give you the value in amperage of the heater.
8,33 Amps
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
40 amps
To answer this question the wattage of the block heater must be stated. Amps = Watts/Volts.
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
45000 / 208 /sqrt(3) = 125A per phase this is probably called a boiler unless it has a 2000Gallon tank
30
The electric heater will have power rated in Watts. The Amps it will draw depends on the voltage system you are using. Can be calculated by formula I (Amps) = P / V In the USA with 110V system a 2400W heater will draw 2400 Watts / 110 Volts = 21.8 Amps In Australia with a 230 V system a 2400W heater will draw 2400 Watts / 230 Volts = 10.4 Amps
The formula you are looking for is I = W/E.
100 KW divided by 415 volts is 241 amperes. Power = voltage times current, so current = power divided by voltage.
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
It means 225 amps on each phase.