Just use Ohm's Law
Voltage = Current x Resistance
Amps = Voltage Divided By Resistance
Amps = 120 / 260
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
In a series circuits, you simply add the the values of each resistor and that is you answer. i.e. - 200 + 86 + 91 + 180 + 150 = 707 ohms
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
If the two resistors are in series, then the larger one is 2 ohms.(The smaller one is 1 ohm. Their combined series total is 3 ohms. 9/3 = 3 amps.)If the two resistors are in parallel, then the larger one is 9 ohms.(The smaller one is 4.5 ohms. The combined parallel total is 3 ohms. 9/3 = 3 amps.)
To provide 240 ohms of resistance. What those 240 ohms do in an actual circuit depends on the intention of the designer.
Ohm's law: Volts = Amps * Ohms, or Amps = Volts / Ohms 12 volts / 0.5 ohms = 24 amps
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
500 ohms.
If you are looking for the resistance of each resistor in either a series circuit or a parallel circuit you must measure the current I and the voltage V for each resistor. Then calculate its resistance using Ohms Law R = V / I where I = current (Amps), V = voltage (Volts) and R= resistance (Ohms).
A short circuit is an unexpected path of zero resistance between two nodes in a circuit. If you measure the resistance of a resistor, and find that is has zero ohms, but the resistor is supposed to be somthing else, such as 100 ohms, then you can conclude that the resistor is shorted. Keep in mind that the precision of the measurement might be critical. If the resistor is supposed to be 100 ohms, but you get zero ohms, then the answer is easy. If the resistor is 0.001 ohms, but you get zero ohms, then you have to consider the precision of the measurement, the resistance of the wires, etc.
No. The resistance in a series circuit is all the resistor values added together. eg. If two resistors were in a circuit, one was 10 ohms and the other was 30 ohms, the resistance in the circuit would be 30 ohms. Hope this helps!
In a series circuits, you simply add the the values of each resistor and that is you answer. i.e. - 200 + 86 + 91 + 180 + 150 = 707 ohms
Resistance (Ohms) = Potential Difference (Volts) / Current (Amps) So, 12/0.25 = 48 Ohms.
2
No, a resistor isn't measured at all. A resistor has a quality called "resistance" - and that value is measured. Resistance is measured in Ohms.
If the two resistors are in series, then the larger one is 2 ohms.(The smaller one is 1 ohm. Their combined series total is 3 ohms. 9/3 = 3 amps.)If the two resistors are in parallel, then the larger one is 9 ohms.(The smaller one is 4.5 ohms. The combined parallel total is 3 ohms. 9/3 = 3 amps.)
12 volts