16 oz = 1 lb
90 oz = 90/16 = 5.625 pounds per bag
50/5.625 = 8.9 bags
19.8 pounds of hay
About 13 pounds
19.8
Here's the formula: (weight)/100 * 2.2 = pounds of hay per day your answer is 19.8, but that number is only a starting point. your horse may eat more or less in a day, and may need to be restricted because of obesity. free choice hay is best, but be mindful of the wasted hay.
You multiply 2.2 by 9 to get 19.8lbs, or about 20lbs.
This is an impossible question to answer as each horse varies in size and work load. Also bales of hay vary in size, they can be as light as 40lbs and as heavy as 120lbs. So you would have to work out the math and know how many pounds per days your horse eats along with how big the bales are you intend to buy.
It would be 2.2 x 9, so the answer would be 19.8 pounds of hay per day!
2.2 lbs is sufficient for 100 lbs pounds of body weight so:per pound requirement = 2.2/100 = 0.022requirement for 900 lbs body = 0.022 x 900 = 19.8lbs19.8 lb
it depends on how thick the hay is Mr farmer
dot stats that 80000 pounds when halling anything on a tractor
when you buy a hay bale, give the horse 4 flakes per day. i don't know that 2.2 lbs of hay per 100 lbs of body weight though... that would mean it gets 1980 lbs of hay a day and that is definitely wrong!
2.2 x 9 = 19.8 lbs.