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212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
212 centimetres = 6.96 feet
1 hr = 60 min → 212 hr = 212 × 60 = 12720 min
212 km is equal to 131.731 miles.
160 btu's. It takes 1 btu (British Thermal Unit) to change the temperature of 1lb of water 1°. This is referred to as sensible heat. This 1 to 1 ratio does not hold true when changing the state of that water to ice or to steam. Changing the state 1lb of water at 212° to 1lb of steam at 212° you must add 970 btu's and to change 1lb of water at 32° into 1lb of ice at 32° you must add 144 btu's. This is referred to as latent heat.
yes. it do.
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
180
212 - 80 = 132 degrees temperature increase x 1 pound water = 132 BTU
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1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
212 Fahrenheit 100 Celsius
212 degrees is the boiling point of water (Fahrenheit). The 212 concept is based on the book 212 the extra degree by Sam Parker. It illustrates how one extra degree of effort can make a big difference. "At 211 degrees, water is hot. At 212 degrees, it boils. And with boiling water, comes steam. And with steam, you can power a train."
1)This is a 5 part question. The first is realizing that 20F to 32F uses .5BTU per pound per degree. That means it takes 32-20=12*.5=6BTUs to get the ice to 32F. 2)Then you need to know the Latent Heat of Fusion for Ice which is 144BTUs (given). Lets assumes the ice changes from ice to water instantaneously at 32F. 3)Next we calculate the BTUs from 32F to 212F. Which is 1BTU per pound per degree F. 212-32=180 so it take 180BTUS. 4)Next we have to use the Latent Heat of Vaporization of water which will say instantaneously converts water to vapor. This takes 970BTUS (given). 5)Then we calculate the BTUS from 212F to 220F. Which is .5BTUs per pound per degree F which is 220-212=8*.5=4BTUs...... Finally add up all the BTUs and you get 6+144+180+970+4=1304BTUs.
Water turns to steam (or in other words, it boils) at 100 degrees Celsius or 212 degrees Fahrenheit.
The temperature of steam depends on the pressure of the system. Higher pressure steam can get super hot. Steam at atm is around 212 degree F, like boiling water.