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1 BTU is required to raise 1lb of water 1 degree F in 1 hour.

212-75=137 degrees

600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water.

To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water

970 btu x 600 lbs water = 582,000 btu

Answer - 582,000 btu+ 82,200 btu = 664,200 btu's

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Q: How many Btu are required to change 600 pounds of water at 75 degrees F to steam at 212 degrees F?
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Related questions

How many btus are required to change five pounds of ice at 20 degrees to steam at 220 degrees?

6,520 Btus


How many BTU will it take to change 10 pounds of ice at 20 degrees to steam at 220 degrees?

To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.


How many btus are required to change 5 pound of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit?

To change 5 pounds of ice at 20°F to steam at 220°F, you will need to go through multiple phases: raise ice temperature to 32°F, melt ice to water at 32°F, raise water temperature to 212°F, and then convert water to steam at 212°F to steam at 220°F. The total heat required, in BTUs, is around 503 BTUs per pound of ice, which translates to about 2515 BTUs for 5 pounds of ice.


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How many btus are requiier to change five pounds of ice 20f to steam at 220f?

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