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For water, the heat of fusion is 80 cal/g. So in other words, this is how many calories are needed to melt 1 gram of water that is frozen. Conversely, when you freeze 1 gram of water, you remove 80 calories of heat from it....

So, you multiply the calories needed to unfreeze a gram of water by the number of grams you have. In this case, 80 * 25 = 2000 Calories

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13y ago
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13y ago

It takes 80 calories per gram ( that is called the heat of fusion of ice)

80 x 25 = 2000 grams

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Q: How many calories are required at 0 degree celsius to melt an ice cube with a mass of 25grams?
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