The simple beginning is that the definition of a calorie is "the energy required to raise the temperature of 1g of water 1°C." Therefore, the energy required to raise 17g of water 32°C: 17*32=544 cal. However, the question asked about ice. There is an extra bit of energy required for the change of physical state. The energy required to convert 1 gram of ice at 0°C to liquid water at 0°C is called the "latent heat" and is equal to about 80 cal. To convert 17g of ice, we multiply this together: 17g * 80cal/g = 1360 cal. So, we add this energy required for the change of state to the energy required to raise the listed quantity to the required temperature and we get 544 cal + 1360 cal = 1904 cal, assuming no heat is lost to the environment.
I hope this clarifies some things.
323.888 degrees celsius
60 degrees Fahrenheit = 15.5555556 degrees Celsius
180 degrees Celsius is 381.6 degrees Fahrenheit.
This heat is 51, 33 cal.
You can use this equation to convert Kelvin to degrees Celsius: ºK - 273.15 = ºC
Can you help
Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories
The number of calories required will depend on the mass of water which is to be heated.
700
If you convert 97.5 degrees Fahrenheit into Celsius you have 36.38 degrees Celsius.
323.888 degrees celsius
Assuming standard atmospheric pressure, 2260 kilojoules.
100 degrees Celsius = 212 degrees Fahrenheit
60 degrees Fahrenheit = 15.5555556 degrees Celsius
350 degrees Fahrenheit = 176.6 degrees Celsius.
To convert from Celsius to Kelvin, you add 273. To convert from Kelvin to Celsius, you subtract 273.
To convert from degrees Celsius to degrees Kelvin, add 273.15. In this instance:4 + 273.15 = 277.15Therefore, 4 degrees Celsius is equal to 277.15 degrees Kelvin.