Q: How many combinations can 8 and 3 get to 140?

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8

3*5*8 = 120

Since there are 3 numbers to choose from, there will be 2^3 = 8 combinations. This includes the null combinations which you may not wish to include in the count.

The answer is 10C3 = 10*9*8/(3*2*1) = 120 combinations.

8C3 = 56 of them

In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.

Two . . . . . 38 and 83.

There are only four combinations but there are 8 permutations.

You can get 50 with 3/8"x3/8" remaining.

There are 8*7/(2*1) = 28 combinations.

6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations

Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.Out of the 8 possible combinations, three are favorable: HTT, THT, TTH. Therefore, the answer is 3/8.

(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations

Assuming that the eight numbers are all different and that none of them are zero, the number of combinations is 8C3 = 8!/(3!*5!) where n! = 1*2*3*...*n the number is 8*7*6 / (3*2*1) = 56

There are 10 choices for the first number, 9 for the second and 8 for the third. 10*9*8=720 possible combinations.

For the permutation the equation is (8!)/(5!) assuming there is no replacement. Which is 8*7*6 = 336 For combinations the equation is (8!)/((5!)(8-5)!) = (8!)/((5!)(3)!) = (8*7*6)/(6) = 56

The number of combinations is 10C4 = 10*9*8*7/(4*3*2*1) = 210

10C6 = 10*9*8*7/(4*3*2*1) = 210 combinations.

There are 9C3 = 10*9*8/(3*2*1) = 120 of them.

9

There are 125970 combinations and I am not stupid enough to try and list them!

17.5

27

4

7+8+3+55+67 = 140 140/5= 28. 7-8-3-55-67=7-(8+3+55+67)=7-133=-126; -126/5=-25.2

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