Q: How many combinations can you get out of 40 numbers in groups of 6?

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I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.

Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.

There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.

By making a number tree that could have as many as 1,000,000 combos.

The answer is 40!/[10!*(40-10)!] where n! represents 1*2*3*...*n. The number of combinations = 40*39*38*37*36*35*34*33*32*31/(10*9*8*7*6*5*4*3*2*1) = 847,660,528

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There are 12,033,222,880 of them.

I doubt it. You can get 7,676,760 different groups of 6 numbers out of a bucket of 40 numbers. No website is going to give you that much output for a single input.

Assuming that the only permitted operation is addition, then there are 4 combinations.

Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.

There are 5245786 possible combinations and I am not stupid enough to try and list what they are!

There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.

(43*42*41*40*39)/(5*4*3*2*1) = 962598

By making a number tree that could have as many as 1,000,000 combos.

The answer is 40!/[10!*(40-10)!] where n! represents 1*2*3*...*n. The number of combinations = 40*39*38*37*36*35*34*33*32*31/(10*9*8*7*6*5*4*3*2*1) = 847,660,528

8 groups of 5 are there in 40.

80

There are an infinite number of groups of numbers whose sum, difference, product, quotient etc. is equal to 40 . But there are not four numbers that equal 40. In fact, there is only one number that equals 40. The number is . . . . . 40 .