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The answer is 40!/[10!*(40-10)!] where n! represents 1*2*3*...*n.

The number of combinations = 40*39*38*37*36*35*34*33*32*31/(10*9*8*7*6*5*4*3*2*1) = 847,660,528

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Q: How many combinations of 10 numbers can you get from 40?
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