The answer is 40!/[10!*(40-10)!] where n! represents 1*2*3*...*n.
The number of combinations = 40*39*38*37*36*35*34*33*32*31/(10*9*8*7*6*5*4*3*2*1) = 847,660,528
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5
You can add the numbers 10, 10, 10, and 10 to get 40. Alternatively, you could use numbers like 5, 15, 10, and 10, or even 1, 2, 3, and 34. There are numerous combinations that can result in a sum of 40.
Assuming that repeated numbers are allowed, the number of possible combinations is given by 40 * 40 * 40 = 64000.If repeated numbers are not allowed, the number of possible combinations is given by 40 * 39 * 38 = 59280.
80
There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.