Depends on the type of sand also if it is wet or dry
1 cubic foot=100 lbs of sand 1728 cubic in.=100 lbs of sand 864 cubic in.= 50 lbs of sand 432 cubic in.= 25 lbs of sand and so on and so on
Divide 4.6 lbs by the lead density in lbs/cubic inch
1000 kg or roughly 500 lbs.
The answer will depend on the units for 2. Whether it is 2 inches, feet or something else. Assuming you mean feet, a 12 foot x 12 foot x 2 foot area contains 288 cubic feet. Sand is usually measured in lbs. One cubic foot of sand weighs about 100 lbs (see related questions below). 288 x 100 lbs = 28800 lbs. This is 14.4 tons of sand.
10.47 cubic inches
ABOUT 43 bags. Dry sand weighs ABOUT 100 lbs per cubic foot- and you need 21.3 cubic feet.
The answer depends on the grain size, lithology, moisture content, and level of compaction of the sand. Generally, one cubic ft of clean (no silt/clay), dry, fine to medium sand that has been compacted to a dense, non-yielding condition will weigh about 110 lbs., while a loose fine to medium sand will weigh about 100 lbs. per cubic foot.
No, it's not possible.
7996.634496 lbs of sand. 500 sq feet is measurement of area which gives no indication as to the shape. For simplicity purposes we will assume the shape is a rectangle with the dimensions of 25 ft by 20 ft. The depth is 2 inches so we need to convert our measurements. 25 ft = 300 in, 20 ft = 240 in, 2 in = 2 in. Volume = 300*240*2 = 144000 cubic inches. Converting cubic inches to feet: 144000 * .00057870 = 83.2896 cubic feet. Now sand has an average of 96.01 pounds per cubic foot. So 96.01*83.2896 = 7996.634496 lbs of sand.
Question can not be ansered correctly without knowing the water content of the soil
30 lbs
49 bags. The density of loose sand is about 90 lbs/cu. ft. There are 27 cu. ft. in a cu. yard. Therefore 27 * 90 equals a total weight of 2,430 lbs. for a cu. yard of sand. Given 50 lbs. per bag of sand, you divide 2430 by 50 and get 48.6 bags of sand. Round up to 49.