The volume of any sphere is [ 4/3 pi R3 ].
We're going to take the easy way out on this one, neglect the thickness of the skin,
and assume that 4.5 inches is the radius of air-chamber in the ball.
Volume = (4/3) (pi) (4.5)3 = 381.7 cubic inches (rounded)
Width = 3 inches so radius = 1.5 inches.Volume = pi*r2*h = 56.5 cubic inches.Width = 3 inches so radius = 1.5 inches.Volume = pi*r2*h = 56.5 cubic inches.Width = 3 inches so radius = 1.5 inches.Volume = pi*r2*h = 56.5 cubic inches.Width = 3 inches so radius = 1.5 inches.Volume = pi*r2*h = 56.5 cubic inches.
A cylinder with a radius of 4 inches and a height of 12 inches has a volume of 603.186 cubic inches.
A cone with a radius of 14 inches and a height of 8 inches has a volume of 1,642 cubic inches.
The volume a cylinder with a radius of 4 inches and a height of 5 inches is: 251.3 cubic inches.
A cylinder with a radius of 7 inches and a height of 48 inches has a volume of 7,389.03 cubic inches.
If its inner radius is 13 inches, the formula for a sphere is 4/3 pi r^3 13x13x13 is 2197, x pi is 6902 cubic inches, /3, x4 is 9202.76 inches cubed
If the basketball is regarded as a perfect sphere then the formula for the volume (V) is V = 4/3πr3 where r is the radius. If the radius is 5 inches then V = 4/3π53 = 500/3π = 523.60 cubic inches (2dp)
A regulation basketball is 455.9 cubic inches.
It is: 4/3*pi*53 = 523.599 cubic inches rounded to three decimal places
Volume of a sphere: 4/3*pi*radius^3 in cubic units
It is: 4/3*pi*53 = 523.599 cubic inches rounded to three decimal places
The height of a cylinder with a volume of 250 cubic inches and a radius of 6 inches is: 2.21 inches.
A sphere with a radius of 3 inches has a volume of 113.1 cubic inches.
-- Measure the radius of the pipe, in inches. -- Measure the length of the pipe in inches. -- The volume of the pipe is (pi) x (radius)2 x (length) cubic inches
A sphere with a radius of 7 inches has a volume of 1,436.76 cubic inches.
Using the formula for the volume of a cylinder (V = πr^2h), and substituting the given values, we can find the radius. Rearranging the formula to solve for the radius gives us r = √(V / (πh)). Plugging in the values, we get the radius as √(146 / (10π)) ≈ 2.15 inches.
If you're using an NBA basketball they have a radius of roughly 4.7 inches which equates to a 103.8in cubic radius. Convert your room to cubic inches 76,500in cubed. 736.99 So 736 basketballs and #737 just barely won't fit.