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Two. If you start from any vertex, the lines to either of the two adjacent vertices will be one of the sides of the original shape. Only the line joining it to the opposite vertex will be a new line - a diagonal. Four vertices might therefore suggest four such lines but remember you're counting each line twice - once from each of its end. From any vertex, you can have only one diagonal - to the next but one vertex. Lines to the next vertex, on either

Q: How many diagonals does a shape with 4 sides have?

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A rhombus.

a square

Any quadrilateral (4-sided shape) has 2 diagonals.

A square is on example. The perpendicular bisectors of the sides and the two diagonals comprie four lines of symmetry.

Only one.

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There are 7*(7-3)/2 = 7*4/2 = 14 diagonals.

rhombus

A rhombus.

a square

Nope, in order for the diagonals to be perpendicular the shape must be a square (which I guess is a type of rectangle :). The diagonals will cross, but not at a 90degree angle, unless the sides are of equal length.Not unless the rectangle has 4 equal sides, making it a squre.

A kite.

Any quadrilateral (4-sided shape) has 2 diagonals.

It is a 2 dimensional shape with 4 sides It has 4 interior angles that add up to 360 degrees It has 2 diagonals

square

A square is on example. The perpendicular bisectors of the sides and the two diagonals comprie four lines of symmetry.

Only one.

A square seems to fit the given description if it also has 4 equal sides