Two. If you start from any vertex, the lines to either of the two adjacent vertices will be one of the sides of the original shape. Only the line joining it to the opposite vertex will be a new line - a diagonal. Four vertices might therefore suggest four such lines but remember you're counting each line twice - once from each of its end. From any vertex, you can have only one diagonal - to the next but one vertex. Lines to the next vertex, on either
a square
A rhombus.
Any quadrilateral (4-sided shape) has 2 diagonals.
A square is on example. The perpendicular bisectors of the sides and the two diagonals comprie four lines of symmetry.
Only one.
There are 7*(7-3)/2 = 7*4/2 = 14 diagonals.
rhombus
a square
A rhombus.
Nope, in order for the diagonals to be perpendicular the shape must be a square (which I guess is a type of rectangle :). The diagonals will cross, but not at a 90degree angle, unless the sides are of equal length.Not unless the rectangle has 4 equal sides, making it a squre.
A diamond shape has four sides, so it is essentially a quadrilateral. The formula for calculating the number of diagonals in a quadrilateral is (n)(n-3)/2, where n is the number of sides. In this case, n = 4, so the calculation would be (4)(4-3)/2 = 2 diagonals. Therefore, a diamond shape could have 2 diagonals drawn within it.
A kite.
Any quadrilateral (4-sided shape) has 2 diagonals.
It is a 2 dimensional shape with 4 sides It has 4 interior angles that add up to 360 degrees It has 2 diagonals
A square is on example. The perpendicular bisectors of the sides and the two diagonals comprie four lines of symmetry.
square
Only one.