18
The answer is 7C5 = 21.
The first member chosen can be any one of 1,514 students.The second member chosen can be any one of the remaining 1,513 students.The third member chosen can be any one of the remaining 1,512 students.So there are (1,514 x 1,513 x 1,512) ways to choose three students.But for every group of three, there are (3 x 2 x 1) = 6 different orders in which the same 3 can be chosen.So the number of `distinct, unique committees of 3 students is(1514 x 1513 x 1512) / 6 = 577,251,864
Four people can be selected from a pool of 8 people in (8 x 7 x 6 x 5) = 1,680 ways.But there are (4 x 3 x 2) = 24 ways to pick the same four people.So you can actually form only 1,680/24 = 70 different 4-person debate teamsfrom a group of 8 students.
7
Not necessarily. The difference may be genuine and that is not the "fault" of the assessment.
2 groups. 2 x 3= 6
There are 2300 possible combinations.
WHY!!!!!!!!!!!!!
Socialist
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SDS. Students for a democratic society.
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a group of students was asked
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A group of students were
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