Looks like here you should be using the equation for a combination rather than a permutation because order does not matter. Here is the equation for combinations: nCr = n!/(r!*(n-r)!) where n= the total number being chosen from (50) and r= the number that can be chosen at one time (5).
50C5 = 50!/(5!*(50-5)!) -> 50C5= 2118760. There are 2118760 ways to choose 5 numbers from the numbers 1-50.
Since a number can have infinitely many digits, there are infinitely many possible combinations.
Three combinations: 23, 24 and 34
4*3*2*1 = 24 different combinations.
there are 13,983,816 combinations.
The number of combinations - not to be confused with the number of permutations - is 2*21 = 42.
To find the total number of different combinations of shirts and pants, you multiply the number of shirts by the number of pants. With 8 shirts and 6 pants, the calculation is 8 x 6, resulting in 48 different combinations.
The number of 4 different book combinations you can choose from 6 books is;6C4 =6!/[4!(6-4)!] =15 combinations of 4 different books.
8C6 = 28
Since 0 cannot be in the first place of the 4-digits number, we have 9 x 10 x 10 x 10 = 9,000 combinations.
If every number can be used as many times as you like, there are 104 = 10000 different combinations. If each number can only be used once, there are 9!/(9 - 4)! = 5040 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
Number of combinations = 45C6 = 45!/6!(45-6)! = 8,145,060