89,999 different numbers i guess
Using the digits 1, 3, and 5 exactly once, you can create different 3-digit numbers by permuting these digits. The number of permutations of 3 distinct digits is calculated as 3! (3 factorial), which equals 6. Therefore, the different numbers you can create are: 135, 153, 315, 351, 513, and 531. Thus, there are 6 different numbers that can be formed.
There are 192.
6 2-digit numbers (13/15/35/53/51/31)
6 if all digits are different, 27 otherwise.
98765.
If you want 4-digit numbers, there are 24 of them.
There are 192.
6 2-digit numbers (13/15/35/53/51/31)
1x+4y=
6 if all digits are different, 27 otherwise.
98765.
9
2 * 2 * 2 * 2 It's not possible to make 16 without using the same numbers twice or without using whole numbers.
Well honey, you've got 4 digits there, so you can form 4! (4 factorial) which is 24 numbers. That's right, you can make 24 different combinations with those digits. Math can be fun when you've got some sassy numbers to play with!
456, 546 and 564 are three of the four possible even numbers.
Ten different digits can be used to make 10C4 = 10*9*8*7/(4*3*2*1) = 210 four-digit numbers. Either numbers starting with 0 are permitted or the 10 digits do not contain a 0.
To create the numbers 1-100 using the digits 2, 0, 1, and 2, you can use various combinations and operations. For example, you can form numbers like 1 (by using 2-2+1), 2 (using one of the 2s), 10 (by combining 2 and 0), and higher numbers such as 20 or 21. By creatively using addition, subtraction, and combinations of the digits, you can generate many numbers up to 100. However, some numbers may not be possible with the given digits and operations.