It is 415968.
The four digits can be used to produce infinitely many different numbers if repetition is permitted. Without repetition, there are 24 possible numbers. A lot more can be produced if the numbers are combined using binary oprations, fore example, 19 * 8/4 = 19*2 = 38.
This is permutations with repetition. The answer is 4^4 = 256 total permutations. Since 2 of the digits used are odd (and 2 are even), then half of the possibilities will be odd: 128 odd numbers.
If repetition is allowed and order is important, then you have essentially a base-4 number system, with the numbers ranging from 00004 to 33334. The quantity of permutations in this example is 44 = 256. If repetition is not allowed, but order is important, then it is 4! = 24. * * * * * The above answer is perfectly correct. But, as stated in the answer, for permutations. However, according to the mathematical definition of combinations (as opposed to permutations), the order is irrelevant to combinations. 1234 is the same as 1423 or 4213 etc. Consequently, there can be only one 4-number combination from 4 numbers
If all letters and numbers are allowed, the possibilities are 26x26x10x10x10x10. So: 6760000 different plates.
the least number is 210 which is divisible by four different prime numbers.
If leading zeros are allowed, then you have 0000 through 9999 which is 10,000 numbers.If leading zeros not allowed: the smallest four-digit number is 1000, eliminating 0000 through 0999 (one thousand numbers are not allowed), so it is 9,000 numbers.
Total possible 4-digit numbers= 1000, 1001,...,9999 = 9000 Total with same digit numbers = 1111,2222,...,9999 = 9 9000 - 9 = 8991
Many bank cards have different structures to their numbers. Some will be longer and have different breaks. The typical is 16 numbers broken into four brackets of four numbers. Example: 1111 2222 3333 4444
With whole numbers, four.
6 if order doesn't matter
Assuming you mean four different numbers, 0.123
6 x 6 x 6 x 3 = 648 6 because the first digit can be any of the numbers 6 again, because the second digit can be any of the numbers 6, again, because the third digit can be any of the numbers 3, because the fourth/last digit can only be 2, 4, or 6
Assume that the question is really looking for an "odd" number, (not an "old" number).Then it's [ 1001 ].
(4 x 3 x 2 x 1) = 24 of them. If repetition were allowed, then there would be (4 x 4 x 4 x 4) = 256 of them.
105105 is divisible by 5 different prime numbers.
All of them, but it does depend on what operators are allowed.