24 ways.
4. There are four ways to draw one king and only one way to draw 4 queens.
There are 65,780 ways.
1/25
All of them. LOL
37 cards.
4. There are four ways to draw one king and only one way to draw 4 queens.
There are 65,780 ways.
1/25
There are 2 black queens and 26 red cards in a standard deck. Therefore the probability is 28/52 = 7/13 = 53.85%
There are 15,820,024,220 ways.
There are 4 queens in 52 cards so the odds of picking a queen in one draw if 4/52. Now once you have picked a queen, there are 3 queens left and 51 cards. So 4/52 x 3/51 = 1/221 = 0.45 %
The answer depends on how many cards are drawn, whether that is with or without replacement, whether the cards are drawn at random. If only one card is drawn, the probability is 0. If 51 cards are drawn, the probability is 1. If two cards are drawn, at random, and the first is not replaced, the probability is (2/52)*(1/51) = 2/2652 = 0.00075, approx.
The probability of drawing three black cards from a standard pack depends on:whether the cards are drawn at random,whether or not the drawn cards are replaced before the next card is drawn,whether the probability that is required is that three black cards are drawn after however many draws, or that three black cards are drawn in a sequence at some stage - but not necessarily the first three, or that the first three cards cards that are drawn are black.There is no information on any of these and so it is not possible to be certain about the answer.The probability of drawing three black cards, in three random draws - without replacement - from a standard deck, is 0.1176 approx.
All of them. LOL
The answer depends on:whether or not the cards are drawn at random,whether or not the cards are replaced before drawing another,how many cards are drawn.If 45 cards are drawn, without replacement, the event is a certainty.
37 cards.
The probability depends on:whether the cards are drawn randomly,how many cards are drawn, andwhether the cards are replaced before drawing the next card.If only 2 cards are drawn randomly, and without replacement, the probability is 0.00075 approximately.