Five people can stand in a line in 5! (5 factorial) different ways. This is calculated as 5 × 4 × 3 × 2 × 1, which equals 120. Therefore, there are 120 different arrangements for the 5 people in a line.
36
5040
The number of ways 8 people can stand in line to limbo is calculated using the factorial of 8, denoted as 8!. This is because each person can occupy any position in the line, leading to 8 choices for the first position, 7 for the second, and so on. Therefore, 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320. Thus, there are 40,320 different ways for 8 people to stand in line to limbo.
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".
420
36
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
If the people are always facing forward? 24 ways.
5040
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".
It usually depends on how many people are there.
420
There are 7 people who could stand first, with 6 people who could stand second for each of those first people, with 5 people who could stand third for each of those first two people, and so on, until with 1 person left who could stand seventh for each of the first six people. This gives 7 × 6 × 5 × ... × 1 = 5040 ways.
3 items (or people) can line up in 6 different sequences. 6 items (or people) can line up in 720 different sequences.
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
120
First place can be any of 6, second any of 5 etc. 6 x 5 x 4 x 3 x 2 = 720 different ways!