5040
36
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".
Five people can stand in a line in 5! (5 factorial) different ways. This is calculated as 5 × 4 × 3 × 2 × 1, which equals 120. Therefore, there are 120 different arrangements for the 5 people in a line.
128
The number of ways 8 people can stand in line to limbo is calculated using the factorial of 8, denoted as 8!. This is because each person can occupy any position in the line, leading to 8 choices for the first position, 7 for the second, and so on. Therefore, 8! = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 40,320. Thus, there are 40,320 different ways for 8 people to stand in line to limbo.
There are n! (n factorial) ways that n people can stand in line. So six people can stand in line in: 1*2*3*4*5*6 = 720 different ways
36
If the people are always facing forward? 24 ways.
Not sure what a strait line is! Five people can stand in a straight line, with Jessie third in 24 ways if you ignore left-to-right and right-to-left "reflections".
Five people can stand in a line in 5! (5 factorial) different ways. This is calculated as 5 × 4 × 3 × 2 × 1, which equals 120. Therefore, there are 120 different arrangements for the 5 people in a line.
128
4*3*2*1 = 24 ways.
There are 7 people who could stand first, with 6 people who could stand second for each of those first people, with 5 people who could stand third for each of those first two people, and so on, until with 1 person left who could stand seventh for each of the first six people. This gives 7 × 6 × 5 × ... × 1 = 5040 ways.
I make it 136 ways.
24 ways
10 people can line up in (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2) = 3,628,800 different ways.
720