I'll give you a clue because I am wary of doing others' homework for them.
There are 2 possible solutions:
1) The number of faces is odd so it must have a base and an apex.
If one face is its base, there must be 4 more faces. Seems familiar?
If the two statements above are right the base must be a quadrilateral of some sort.
you should now be able to deduce what it is - and so count the edges!
2) Let us suppose it has no apex but is all edges. Then it must have 2 ends, rather than an end and an apex.
So that leaves the ends joined by 3 faces.
Which rather limits the number of edges on each end.
You should now be able to deduce that too!
It is a triangular prism that has 5 faces, 6 vertices and 9 edges
5
Triangular Prisim
Edges: 8 Faces: 5 Vertices: 5
There is not a polyhedron with the given number of faces, edges and vertices.
A polyhedron that has twice as many edges as faces is known as a triangular prism. In a triangular prism, there are 5 faces (two triangular bases and three rectangular lateral faces) and 9 edges. This means the number of edges (9) is indeed twice the number of faces (5), satisfying the condition of having twice as many edges as faces.
A dodecahedron is a 12 side polyhedron. A regular dodecahedron has regular pentagons (5 sides) for each face.
A pyramid has 5 faces, 5 corners and 8 edges corners and faces are always the same
Yes because it has 5 faces, 8 edges and 5 vertices
It will have 300 edges and 200 vertices
Assuming the shape is a simply connected polyhedron, there are 6 faces. A triangular dipyramid, for example.
If it is a simply connected polyhedron then it is a quadrilateral based pyramid and so has 5 faces.If it is a simply connected polyhedron then it is a quadrilateral based pyramid and so has 5 faces.If it is a simply connected polyhedron then it is a quadrilateral based pyramid and so has 5 faces.If it is a simply connected polyhedron then it is a quadrilateral based pyramid and so has 5 faces.