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So we have 5 places to fill since it's a 5 digit number. We want the last digit to be a 0, 2, 4, or 6 so it'll be even. That means we have 6 digits to choose from for the first digit, 5 to choose from for the second, 4 to choose from for the third, and 3 to choose from for the second to last, and 4 to choose from for the last digit since it's 0, 2, 4, or 6. So the answer is 6 * 5 * 4 * 3 * 4 = 1440.

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12y ago
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Q: How many even 5-digit numbers can be formed from the digits 0 1 2 3 4 5 and 6 if each digit can be used only once?
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