One Cubic foot is 1' x 1' x 1'. So it depends on how deep you are going. If you have
1 cu ft. of sand it will cover 12 sq.ft. at 1" thick. 4 sq.ft coverage at 3" thick. So depending on details you can't really answer your question. Hope this helps.
21 ft*10 ft*2 in = 21 ft*10 ft * (1/6) ft = 21*10/6 cu ft = 35 cu ft.
27 cu ft = 1 cu yd
27 cu feet = 1 cu yard 1260 cu ft = 1260/27 = 46.67 (462/3) cu yards
None - or to put it another way:Cubic feet of what? There are more kg in 1 cu ft of mercury than 1 cu ft of hydrogen.Kg are a measure of weight.Cubic feet are a measure of volume.Weight and volume are related by density (of the substance).
1 cubic yard = 27 cubic feet = 13 and 1/2bags.
21 ft*10 ft*2 in = 21 ft*10 ft * (1/6) ft = 21*10/6 cu ft = 35 cu ft.
The cubic yards require that the width of the pile also be given. Assume the width of the pile of dirt, w , is 80 feet. V = ( L ) ( w ) ( h ) V = ( 300 ft ) ( 80 ft ) ( 10 ft ) = 240 x 10^3 cu ft V = ( 240 x 10^3 cu ft ) ( 1 cu yd / 27 cu ft ) V = 8889 cu yd <------------------
100 cu ft × 2 = 200 cu ft.
If the dimensions given are inches, there are 49.11 cu. ft. If they are in feet there are 84,864 cu. ft.
sq feet to sq yards cu ft to cu yards you need depth added to your sq ft to get cu ft such as 70 sq ft x 4 in deep = 23.33 cu ft =.086 cu yd
A little more than one cubic yard of crushed rock is needed. (10 ft x 6 ft x 1/6 ft = 10 cu ft = 1 cu yd + 1 cu ft)
27 cu. ft. = 1 cu. yd.
5 cu/yrds x 27 cu/ft = 135 cu/ft
1 ft = 12 in → 1 in = 1/12 ft Volume required to cover is 90 sq ft × 1 in = 90 sq ft × 1/12 ft = 7.5 cu ft → number of bags = 7.5 cu ft ÷ 0.8 cu ft/bag = 9.375 bags → you need to buy 10 bags
51840 cu ft
797 cu yards = 797 * 33 cu feet = 21519 cu ft.
Cubic feet measure volume. It is not possible to measure the number of feet in cubic feet. Cubic feet are in three dimensions. Feet are in one dimension. (And square feet are in two dimensions.)