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The least possible length of fence that can enclose 20 acres is 3,308.75 ft.That's if the field is circular.If the field is square, then it takes 3,733.5 ft.If it's a rectangle ... straight sides but not a square ... then the perimeter can beanything more than 3,733.5 ft, depending on the shape of the rectangle. The areadoesn't tell you what the perimeter has to be.
The question suffers from a few problems:Problem #1:The closer we read the question, the less sense it makes. What is 0.25 miles apart ?The pieces of the field ? The fence-posts ? Nothing we can think of seems like a reasonableassumption. So you know what ? We're just going to ignore that part of the question,and talk about the length of fencing you'll need.Problem #2:The area doesn't tell you the perimeter. Your 25 acres could have an infinitenumber of different shapes and sizes, and every one of them would take adifferent amount of fencing to enclose it.If you want to use the absolute minimum amount of fence, then you want the25 acres in the shape of a circular field, 392.5 yards in diameter. Then thecircumference of the circle is 3,700 ft. = 1,233.1yards. (rounded)If you definitely want straight sides around the plot, then you want it in theshape of a square with sides of 347.9 yards. The perimeter of the square is4174.2 ft = 1,391.4 yards. (rounded)That's the minimum. If it's a rectangle and not square, then the longer andskinnier it is, the more fence it needs ... while keeping the same constant areaof 25 acres. For example:-- If it's 242 yds by 500 yds, it's 25 acres, and you need 1,484 yards of fence to enclose it.-- If it's 121 by 1,000 yds, it's still 25 acres, but you need 2,242 yards of fence to enclose it.-- If it's 44 by 2,750 yds, it's still 25 acres, but you need 5,588 yards to enclose it.
It depends on what shape the one acre is, and what kind of fence is to be installed. For example, a simple livestock fence consisting of woven wire and a three-strand barbed wire on top, and assuming the acre is square will require 835 feet of woven wire, 2,500 feet of barbed wire, 12 corner posts, and about 70 steel T-posts. Different shapes of field will change this, and different types of fencing require different materials.
A rectangle.
the sides of the fence are parallel to the rows of crops.
i dont no
The length of the field is 250 meters. As we know the field is a rectangle, you can divide the amount of fencing in 2, which would be 400 meters. This will provide you with enough fencing for one end and one side. To determine the actual length of the side you would take your 400 meters and subtract the end length which is 150 meters, leaving you with a side length of 250 meters.
The least possible length of fence that can enclose 20 acres is 3,308.75 ft.That's if the field is circular.If the field is square, then it takes 3,733.5 ft.If it's a rectangle ... straight sides but not a square ... then the perimeter can beanything more than 3,733.5 ft, depending on the shape of the rectangle. The areadoesn't tell you what the perimeter has to be.
oval or rectangle (usualy rectangle)
The question suffers from a few problems:Problem #1:The closer we read the question, the less sense it makes. What is 0.25 miles apart ?The pieces of the field ? The fence-posts ? Nothing we can think of seems like a reasonableassumption. So you know what ? We're just going to ignore that part of the question,and talk about the length of fencing you'll need.Problem #2:The area doesn't tell you the perimeter. Your 25 acres could have an infinitenumber of different shapes and sizes, and every one of them would take adifferent amount of fencing to enclose it.If you want to use the absolute minimum amount of fence, then you want the25 acres in the shape of a circular field, 392.5 yards in diameter. Then thecircumference of the circle is 3,700 ft. = 1,233.1yards. (rounded)If you definitely want straight sides around the plot, then you want it in theshape of a square with sides of 347.9 yards. The perimeter of the square is4174.2 ft = 1,391.4 yards. (rounded)That's the minimum. If it's a rectangle and not square, then the longer andskinnier it is, the more fence it needs ... while keeping the same constant areaof 25 acres. For example:-- If it's 242 yds by 500 yds, it's 25 acres, and you need 1,484 yards of fence to enclose it.-- If it's 121 by 1,000 yds, it's still 25 acres, but you need 2,242 yards of fence to enclose it.-- If it's 44 by 2,750 yds, it's still 25 acres, but you need 5,588 yards to enclose it.
It depends on what shape the one acre is, and what kind of fence is to be installed. For example, a simple livestock fence consisting of woven wire and a three-strand barbed wire on top, and assuming the acre is square will require 835 feet of woven wire, 2,500 feet of barbed wire, 12 corner posts, and about 70 steel T-posts. Different shapes of field will change this, and different types of fencing require different materials.
335 feet
The perimeter of the rectangular field is 2*(L+W) = 2*(120+50) = 2*170 = 340 feet
Rectangle.
A rectangle.
The out of bounds line runs around a football field but never moves.
No, a soccer field is a rectangle, not a square.