132 gallons
16 : 84 of 60 gallons = 9.6 : 50.4 gallons
80 : 20 of 132 gallons = 105.6 : 26.4 gallons
added = 115.2 : 76.8 gallons = 1.5:1 ( 60:40)
10 gallons..
t = number of liters of 30% acid solution s = number of liters of 60% acid solution t+s=57 .30t+.60s=.50*57 t=57-s .30(57-s)+.60s=.50*57 .30*57 -.30s +.60s = .50*57 .30s = .50*57 - .30*57 = .20*57 s = .20*57/.30 = 38 liters of 30% solution t = 57 - s = 57-38 = 19 liters of 60% solution
tv=tv, so 0,25x50=0,1v; v=12,5/0,1; v=125ml of water. So the solution must have 125ml of water for the title to be 10%, then we must add 125-50ml(75ml) of water to it.
You obtain a solute solution in the desired and possible solvent.
2.5 is the answer....5(.04)+.10(x)= .06(5+x).2+.1x=.3+.06x.04x=.1or 4x=10 so x =2.5
25 gallons
50 gallons @ 3% must be added.
10 gallons..
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
You will need 3.2 gallons.
614
630
70gallons
10
x=45
Make an equation: x(.10) = 50gal(.15) Solve algebraically: x = 75 gal
pH less than 7