0
How many gallons of antifreeze must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 80 percent antifreeze?
Wiki User
∙ 12y ago
Find the overall balance of antifreeze: amount of antifreeze to start with + the amount of pure antifreeze to add = amount of antifreeze in the final solution
Let X be the amount of pure antifreeze to add in gallons.
(70 * 0.25) + X = 0.80 * (70+X)
17.5 + X = 56 + 0.8X
0.2X = 56 - 17.5
0.2X = 38.5
X = 38.5/0.2 = 192.5 gallons
Wiki User
∙ 12y ago
Add your answer:
Earn +20 pts
How many gallons of a 90 percent antifreeze solution must be mixed with 70 gallons of 15 percent antifreeze to get a mixture that is 80 percent antifreeze?
Suppose x gallons of 90% antifreeze is mixed. Then total volume of mixture = x + 70 gallons and total antifreeze in mixture = 0.9*x + 0.15*70 = 0.9x + 10.5 Concentration of mixture = (0.9x + 10.5)/(x + 70) which is 80% or 0.8 So 0.9x + 10.5 = 0.8x + 56 that is 0.1x = 45.5 or x = 455 gallons
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Let X = gallons of 50% antifreeze .5X + .1(70) = .4 (X + 70) .5X + 7 = .4X + 28 .1X = 21 X = 210 GALLONS
How many gallons of a 80 percent antifreeze solution must be mixed with 60 gallon of 15 percent antifreeze to get a mixture that's 70 percent antifreeze?
330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 40 percent antifreeze?
105 gallons. Let the multiple of 70 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 70 x 1.5 = 105 gallons.
How many gallons of 70 percent antifreeze solution should be mixed with 60 gallons of 10 percent antifreeze to get a mixture that is 60 percent antifreeze?
.70x+.10(60)=.60(x+60) let x= number of gallon at 70% .7x+6=.6x+36 .1x=30 x=300
How many gallons of a 90 percent antifreeze solution must be mixed with 80 gallons of 25 percent antifreeze to get a mixture that is 80 percent antifreeze?
614
How many gallons of a 50 percent antifreeze solution must be mixed with 70 gallons of 30 percent antifreeze to get a mixture that is 40 percent antifreeze?
70gallons
How many gallons of a 90 percent antifreze solution must be mixed with 90 gallons of 10 percent antifreeze to get a mixture that is 80 percent antifreeze?
630
How many gallons of a 90 percent antifreeze solution must be mixed with 70 gallons of 15 percent antifreeze to get a mixture that is 80 percent antifreeze?
Suppose x gallons of 90% antifreeze is mixed. Then total volume of mixture = x + 70 gallons and total antifreeze in mixture = 0.9*x + 0.15*70 = 0.9x + 10.5 Concentration of mixture = (0.9x + 10.5)/(x + 70) which is 80% or 0.8 So 0.9x + 10.5 = 0.8x + 56 that is 0.1x = 45.5 or x = 455 gallons
How many gallons of a 80 percent antifreeze solution must be mixed with 90 gallons of 25 percent antifreeze to get a mixture that is 70 percent antifreeze?
Let X = gallons of 80% antifreeze Then 0.80X + .25 (90) = .70( 90 + X) .80X + 22.5 = 63 + .70X .1X = 41.5 X = 415 gallons
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 10 percent antifreeze to get a mixture that is 40 percent antifreeze?
Let X = gallons of 50% antifreeze .5X + .1(70) = .4 (X + 70) .5X + 7 = .4X + 28 .1X = 21 X = 210 GALLONS
How many gallons of a 80 percent antifreeze solution must be mixed with 60 gallon of 15 percent antifreeze to get a mixture that's 70 percent antifreeze?
330 gallons of 80% antifreeze mixed with 60 gallons of 15% antifreeze will provide 390 gallons of 70% antifreeze. Let the multiplier of 60 gallons be x, then considering the percentages of antifreeze in the solutions: (15 + 80x) ÷ (1 + x) = 70 ⇒ 15 + 80x = 70 + 70x ⇒ 10x = 55 ⇒ x = 5.5 Therefore mix 60 x 5.5 = 330 gallons of 80% antifreeze.
How many gallons of a 50 percent antifreeze solution must be mixed with 90 gallons of 25 percent antifreeze to get a mixture of 40 percent antifreeze?
135 gallons. Let the multiple of 90 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 90 x 1.5 = 135 gallons.
How many gallons of 50 percent antifreeze solution must be mixed with 70 gallons of 25 percent antifreeze to get a mixture that is 40 percent antifreeze?
105 gallons. Let the multiple of 70 gallons to add be x, then using the percentages of antifreeze in the solutions: (25 + 50x) ÷ (1 + x) = 40 ⇒ 25 + 50x = 40 + 40x ⇒ 10x = 15 ⇒ x = 1.5 Therefore add 70 x 1.5 = 105 gallons.
How many gallons of a solution that is 75 antifreeze must be mixed with 4 gallons of a 30 solution to obtain a mixture that is 50 antifreeze?
You will need 3.2 gallons.
How many gallons of 70 percent antifreeze solution should be mixed with 60 gallons of 10 percent antifreeze to get a mixture that is 60 percent antifreeze?
.70x+.10(60)=.60(x+60) let x= number of gallon at 70% .7x+6=.6x+36 .1x=30 x=300
How many gallons of 50 percent antifreeze solution must be mixed with 100 gallons of 20 percent antifreeze to get a mixture that is 50 percent antifreeze?
You will never get it there. However much 50% you have, any amount of 20% in the mix will reduce the total below 50%. So, throw away the 20% and just use the 50% on its own.
