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What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
What is the mass in grams of 2.38 moles of Al2O3?
The answer is 242,6648 g.
Calculate the number of grams of Al in 371 g of Al2O3?
about 267.12g
What does al2o3 stand for?
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
What is the mass in grams of 9.27 moles of Al2O3?
The molar mass of Al2O3 is 101.96 g/mol. To calculate the mass of 9.27 moles of Al2O3, you would multiply the moles by the molar mass: 9.27 mol x 101.96 g/mol = 945.442 g. So, the mass of 9.27 moles of Al2O3 is approximately 945.442 grams.
How do you calculate the number of grams of Al in 286 g of Al2O3 .?
Aluminium oxide has 52, 94 % aluminium.286 g of Al2O3 contain 151,412 g aluminium.
What is the gram formula mass of Al2O3?
The molar mass of aluminium oxide is 101,947 83.
What is the mass of AlCl3 that is produced when 25.0 grams of Al2O3 reacts with HCl according Al2O3 6HCl to 2ALCl3 3H2O?
25 / 102 = x / 267 x = 267 (25/102) = 65.4 g
How many grams of oxygen are in 5.75 moles of aluminum oxide?
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
If 9 grams of trivalent metal are combined with 8 grams oxygen the atomic weight of the metal will be?
Aluminium oxide, Al2O3; the atomic weight of aluminum is 26,981 538 6.
How many aluminum atoms are in 291.257 grams of Al2O3?
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
How many grams of alcl3 are produced from with 8.0 moles of al2o3. 6cl2 plus 2al2o3 equals 3o2 plus 4alcl3 equals?
8 mol x (4 mol / 2 mol) x 133.5 g / 1 mol = 2136 grams
