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1 x 1022 ym = 1 cm
2.55 grams = 2,550 grams
1.296 grams = 0.001296kg
2068 grams
Grams and grams are the same measurement. Therefore, 61.2 grams is equal to 61.2 grams.
The nitrogen iodide is NI3.
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
1 mole NCl3 = 120.366g NCl3 = 6.022 x 1023 molecules NCl3 8.2 x 1022 molecules NCl3 x 120.366g NCl3/6.022 x 1023 molecules NCl3 = 16g NCl3 rounded to 2 significant figures
1.64×1022 molecules
2.05×1022 molecules
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.
As every nitric oxide molecule has three atoms, this amount of molecules have 3.9 x 1022 atoms.
To find the mass, we divide by Avogadro's number to find the amount of moles. We then multiply the moles by the molar mass of the compound which is 60.08 grams. Doing all of this, we get a mass in grams of 5.59 grams.
1.814*1022
The first step is calculating how many molecules of glucose are in 3.00 grams. To do this, you need the molecular mass of the compound (glucose), which is found by adding up the weights of the elements involved in C6H12O6. C6: 12.0 × 6 = 72.0 H12: 1.0 × 12 = 12.0 O6: 16.0 × 6 = 96.0 72.0 + 12.0 + 96.0 = 180.0 grams/mol With this and Avogadro's constant (6.02 × 1023), we can then convert 3.00 grams of glucose to number of molecules. 3.00 grams ÷ 180.0 grams/mol × (6.02 × 1023) = 1.00 × 1022 molecules of glucose So now we know how many molecules of glucose there are. We also know from the formula that in one molecule of glucose, there are 6 atoms of carbon, 12 atoms of hydrogen, and 6 atoms of oxygen. Number of atoms in one molecule × number of molecules = number of atoms in given amount 6 × (1.00 × 1022) = 6.00 × 1022 atoms of carbon 12 × (1.00 × 1022) = 1.20 × 1023 atoms of hydrogen 6 × (1.00 × 1022) = 6.00 × 1022 atoms of oxygen
The mass is 2.86 grams but the weight will be 0.028 Newtons.
2.50 grams C14H18N2O5 (1 mole C14H18N2O5/294.304 grams)(18 moles H/1 mole C14H18N2O5)(6.022 X 1023/1 mole H) = 9.21 X 1022 atoms of aspartame