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A 1% solution normally contains 1 gram of active ingredient per 100 ml of solution (weight-volume percent) Could also be 1gm per 100 gms (weight-weight percent)- but normally weight-volume is used.
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How many grams of a drug must be used to prepare 3 liters of a 2 percent solution?
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
How many grams of a drug must be used to prepare 5000 milliliters of a 1 percent solution?
You need 50 g of this drug.
What is the number of Grams of 5.5 percent dextrose in a 1L solution of water?
I hope you don't work in a hospital, and I also hope you have passed 7th grade.But, 5% of a 1 L (1000 g) solution would be 50 grams.
1 percent solution of a medication equals how many micrograms?
1 milligrams
How can you express the concentration of a substance mathematically?
In chemistry, the concentration of a substance in solution is determined by molarity, which is symbolized by "M". This indicates the number of moles of a substance dissolved in one liter of a solvent (usually water). For example: - 1 mole of sodium chloride = 58 grams - If 116 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 2-molar (2 M) solution of sodium chloride. - If 232 grams of sodium chloride are dissolved in 1 liter of water, then that solution is a 4-molar (4 M) solution of sodium chloride.
How many grams of a drug must be used to prepare 2 liters of a 1 percent solution?
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
How many grams of a drug must be used to prepare 3 liters of a 2 percent solution?
1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
How many grams of a drug must be used to prepare 5000 milliliters of a 1 percent solution?
You need 50 g of this drug.
How do you determine the number of grams of an active ingredient in a solution based on the percent strength?
1 1/2 cup kidney beans
How many grams of NaCl are needed to to make a NaCl solution 1 percent?
It depends how strong a solution you want to make. The molecular mass of NaCl is 58.44, so for a 1 molar solution you would dissolve 58.44 grams in water and make the volume up to 1 litre. For a 0.1 mol solution you'd take 5.844g to a litre, and a 2 mol solution you'd take 116.88g to a litre of water.
How many grams of sugar in 1 cup of 1 percent milk?
No.
What is the number of Grams of 5.5 percent dextrose in a 1L solution of water?
I hope you don't work in a hospital, and I also hope you have passed 7th grade.But, 5% of a 1 L (1000 g) solution would be 50 grams.
How many grams of salt are in 1 liter of marine solution?
35
How many grams of sulfosalicylic acid are required to prepare 1 liter of 3 solution?
30 grams
How do you calculate normality of percent solution?
Is the makeup of the solution expressed as "percent by mass"? If so, to calculate molarity (or normality), you have to also know the density of the solution Step 1. Lets say the solution is 14%, and the density is 1.09 g/mL. We can write the following: (14 grams solute/100 grams solution) (1.09 grams solution/ mL solution) Step 2. Multiplying and cancelling from step 1 gives you 15.26 grams solute / 100 mL solution. Multiplying top and bottom by 10 gives you 152.6 grams solute per liter. Step 3. Molarity is number of moles per liter. Divide the 152.6 grams of the solute by the forumua weight (or molecular weight) of the solute, and you have the number of moles of solute. This number is therefore the molarity of the solution. If the solution is "percent by volume", the number you have is number of grams per 100 mL. Multiply by 10, and you have grams per liter. Then divide by the formula weight, and you have the molarity.
How many grams are in a liter of solution?
Assuming that the density of the solution in 1 gdm-3 : 1 litre = 1dm3= 1 kg = 1000g
How do you make 10 percent solution from 20 percent solution?
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
