1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
To prepare a 2% solution in 3 liters, you would need 60 grams of the drug. This is calculated by multiplying the volume (3 liters) by the percentage (2%) and converting the result to grams. 3 liters x 2% = 60 grams.
You need 50 g of this drug.
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
42.8 grams of KIO3 and add H2O until the final homogeneous solution has a volume of 2.00 liters
To prepare a 3.8 M HCl solution, you would need to measure 65.36 mol of HCl. You can then dilute this to a final volume of 17.2 L using water. Make sure to wear appropriate protective gear and handle the concentrated HCl solution with caution, as it is a strong acid.
If 1,1 is grams the molarity is 0,317.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
4314.9 grams
0.1125% of polymer solution.
400 mls would require 40g of glucose for a 10% solution and thus 20g for a 5% solution.
To prepare 3 liters of a 2.5 M solution of KCl, you would need to dissolve 187.5 grams of KCl (3 liters * 2.5 moles/liter * 74.55 g/mole) in enough water to reach a final volume of 3 liters. First, measure out 187.5 grams of KCl, add it to a suitable container, and then add water gradually while stirring until the final volume reaches 3 liters. Finally, mix the solution thoroughly to ensure the KCl is completely dissolved.
You need 50 g of this drug.
The percent concentration of the codeine solution is 1.5%. This is calculated by dividing the mass of codeine (30g) by the total mass of the solution (2000g, since 1 liter of water is approximately 1000g) and then multiplying by 100.
To prepare a 5% NaCl solution, you will need 200 grams of NaCl for 4000 mL (4 L) of solution. This is calculated as 5% of 4000 mL, which equals 200 grams.
To prepare a 3% solution of sulfosalicylic acid, you would need 30 grams of sulfosalicylic acid for every 1 liter of solution.
438 grams.
To prepare a 0.100 M solution of trinitrotoluene in 250 ml of solvent, you need 0.025 moles of trinitrotoluene. The molar mass of trinitrotoluene is 227.14 g/mol, so you would need 5.68 grams of trinitrotoluene to make the solution.