1 percent = 10 grams 2 % = 20 grams x 3 liters = 60 grams
Codeine is 299.364 grams per mole; 30 grams in 2 liters is 0.0501 moles per liter.
You need 50 g of this drug.
42.8 grams of KIO3 and add H2O until the final homogeneous solution has a volume of 2.00 liters
First get moles HCl, then get the grams HCl.Molarity = moles of solute/Liters of solution3.8 M HCl = X moles/17.2 Liters= 65.36 moles HCl===============so,65.36 moles HCl (36.458 grams/1 mole HCl)= 2382.89 grams HCl======================and,put this amount, 2382.89 grams, 65.36 moles HCl into the 17.2 liters of solution ( water, I suppose ) 2382.89 grams = 2.38 kilograms. I suppose you could weigh out the HCl in a flask of some sort.
If 1,1 is grams the molarity is 0,317.
1% solution = 1 gram per 100 mL, 10 grams per liter 20 grams
See the two Related Questions to the left for the answer.The first is how to prepare a solution starting with a solid substance (and dissolving it). The second question is how to prepare a solution by diluting another solution.
4314.9 grams
0.1125% of polymer solution.
Molarity = moles of solute/Liters of solution 0.75 M KCl = moles KCl/2.25 Liters = 1.6875 moles KCl (74.55 grams/1 mole KCl) = 126 grams of KCl needed
Molarity = moles of solute/Liters of solution ( 220.0 ml = 0.220 Liters ) 0.500 M KOH = moles KOH/0.220 Liters = 0.110 moles KOH (56.108 grams/1 mole KOH) = 6.17 grams solid KOH needed
Codeine is 299.364 grams per mole; 30 grams in 2 liters is 0.0501 moles per liter.
You need 50 g of this drug.
438 grams.
40.8 grams
C7H5N3O6 Molarity = moles of solute/Liters of solution (250 ml = 0.25 Liters ) 0.100 M C7H5N3O6 = X moles/0.25 L = 0.025 moles -------------------------now, 0.025 moles C7H5N3O6 (227.14 grams/1 mole C7H5N3O6) = 5.68 grams TNT ====================a good firecracker!
42.8 grams of KIO3 and add H2O until the final homogeneous solution has a volume of 2.00 liters