None. Pure water has only hydrogen and oxygen.
A gallon and half of water is 5,676 grams
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
15 grams of nitrogen are equal to 1,071 moles.
There are 3785.41 grams in one US gallon
That is 3,628.739 grams.
1 uk gallon = 4.546 litres = 4.546 kg water * 1.28 * 1 000 = 5 818.88 grams 1 us gallon = 3.785 litres = 3.785 kg water * 1.28 * 1 000 = 4 844.80 grams
That depends on what substance, if any, is in the gallon. If the gallon is empty, then the mass in it is zero grams.
1820 grams in a British gallon.
To calculate the grams of water formed, we first need to determine the moles of nitrogen and oxygen produced. Using the given data, we find that 14 grams of nitrogen is equivalent to 1 mole and 8 grams of oxygen is also equivalent to 0.5 moles. In the explosion, these moles of nitrogen and oxygen will combine with hydrogen to form water. Since the molar ratio of hydrogen to nitrogen and oxygen is 2:1, the moles of water produced will be 1 mole (from nitrogen) + 0.5 moles (from oxygen) = 1.5 moles. Finally, converting moles to grams, 1.5 moles of water is equal to 18 grams. Thus, 18 grams of water would form during the explosion.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
Oh, dude, seriously? A 55-gallon drum is a unit of volume, not weight. It's like asking how many pounds are in a gallon of milk. You gotta be more specific, like asking how many pounds of water can fit in a 55-gallon drum or something. But hey, I can tell you there are approximately 208,197 grams in 55 gallons of water if you really wanna know.