c
172.16.1.14 255.255.255.240
The subnet mask on host C is improperly configured.
That depends on the subnet's subnet mask.
Same as subnetting any other class, or a classless network. From the bits originally reserved for the host (16 bits, in the case of a class B address), you "borrow" some bits, that is, you use them to specify the subnet. The remaining bits specify an individual host within a subnet.
222.49.49.0
3
255: 1111_1111 5: 0000_0101 1: 0000_0001 2: 0000_0010 Source IP address: 10.10.5.1 Subnet mask: 255.255.255.0 Subnet: 10.10.5.0 (host subnet) Destination IP address: 10.10.5.2 Subnet mask: 255.255.255.0 Subnet: 10.10.5.0 (destination subnet) The destination subnet address for 10.10.5.0 which is the same subnet as the host. Therefore, the packet stays in the LAN.
24
To determine if the hosts at 172.20.11.250 and 172.20.12.3 are on the same subnet, we need to look at their IP addresses and the subnet mask. If we assume a common subnet mask of 255.255.255.0, then the first three octets (172.20.11 and 172.20.12) indicate they are in different subnets. Since the third octet differs (11 vs. 12), they are not on the same subnet.
32 host per 8 subnet.
It depends on your subnet mask. IP addresses begining with 170 are Class-B networks and if your using classful network boundries, then the network would be 170.3.0.0. But, its unlikely you're using classful boundries these days. The most common subnet uses a 24-bit subnet mask (255.255.255.0). It that's the case, then the network would be 170.3.24.0 There are of course other possibilites- everything depends on the subnet mask.
By changing subnet mask..from 255.255.224.0 to 255.255.240.0 Number of subnetworks increase and the number of host in each subnetwork decreases