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You said between, that means not including either 27 or 42. So 'between' 27 and 29, there is one integer(28). 29-27 = 2, which is one more than the # of integers between. So subtract (42-27) and that will be one more than the integers between.
There are 544 positive integers less than 1,000 that are either divisible by two or by 11.
There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.
either irrational numbers, integers, integers, rational numbers, or whole numbers
It may be either. If any of the integers is zero, the product will be zero. Else, if one or three of the integers is negative, the product will be negative. Otherwise, it will be positive.
If both numbers are positive....yes If either or both numbers are negative ....no
You said between, that means not including either 27 or 42. So 'between' 27 and 29, there is one integer(28). 29-27 = 2, which is one more than the # of integers between. So subtract (42-27) and that will be one more than the integers between.
Yes
An integer is either positive (non-negative), or negative, or zero. There are no negative non-negative integers.
5 and 7.
There are 544 positive integers less than 1,000 that are either divisible by two or by 11.
There is no such thing as consecutive numbers because numbers are infinitely dense. Between any two numbers there is another and so there is no such thing as a "next" number.There are no integers (square or non-square) between any two consecutive integers. There are infinitely many numbers between any two consecutive integers and, if the integers are non-negative, every one of these will be a square of some number so the answer is none. If the integers are negative then the infinitely many numbers will have a square root in the complex field but not in real numbers. In this case the answer is either none or infinitely many, depending on the domain.
either irrational numbers, integers, integers, rational numbers, or whole numbers
It may be either. If any of the integers is zero, the product will be zero. Else, if one or three of the integers is negative, the product will be negative. Otherwise, it will be positive.
It may be either. If any of the integers is zero, the product will be zero. Else, if one or three of the integers is negative, the product will be negative. Otherwise, it will be positive.
No, integers are either positive or negative whole numbers.
Either side works, generally the right though.