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q = (250 g)(0.46 J/gC)(300 C - 27 C) = 3.1 X 104 Joules -------------------------
Violation of 2nd Law
To help in the differential diagnosis of different types of anemia; To assess the severity of anemia and monitor the treatment of patients with chronic anemia; To evaluate protein depletion
The percentage of iron oxide in iron oxide is ... yep, you guessed ... 100%!
An alloy of iron and lead.
0.46 * 1475 = 678.5 Kjoules (The specific heat is given in terms of joules/ gramme/degC, whilst the question refers to 1kg ie 1000g )
When molten iron cools and solidifies, this is called "fusion".
There is not enough information in this problem to answer the question. You must know the mass of the iron to find the amount of joules used to heat the iron.
NO....it cools by itself.
iron was given iron becease it was the best thing tname it
Its its liquid state the iron is "molten" As it cools It looses heat and solidifies.
Where are you getting this specific heat number. With the other numbers there is no cancellation.
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
200 grams
the thermostat heats up and is spring loaded when there is enough heat it will close and stop the heating element, when it cools it opens again and turns the heat back on, hope this helps
iron is in the water that is given to the plants
The answer will depend on its starting temperature and its final temperature.