I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC )
q(Joules) = mass * specific heat * change in temperature Celsius
3 kilograms cast iron = 3000 grams
q = (3000 g)(0.46 J/gC)(120 C - 30 C)
= 124200 Joules (1 kilojoule/1000 joules)
= 124.2 kilojoules of energy needed
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Kilograms and Kelvin (or degrees Celsius).
6.276 kJ
6.276 kJ
19 050 kilograms
The thermal energy of a solid or a volume of liquid is the specific heat of a material multiplied by the object's mass and temperature (absolute). I.E. 1 kg of water at 27 degrees C: specific heat of water is 4.186 Kilojoules per kilogram-degree Celsius. Multiply that by the mass and the absolute temperature (Degrees Kelvin, or 273.15 + degrees Celsius) to get the thermal energy in kilojoules
The answer is 53,683 kJ.
The kilogram (kg) is a unit of mass, and cannot be applied to temperature. However, room temperature is generally regarded as 20 degrees Celsius, which is 68 degrees Fahrenheit, or 293 kelvins.
A glacier is ice, which melts just above 0 Celsius or 32 Fahrenheit.
Fresh water at a temperature of 10 degrees Celsius has a density of 999.70 kilograms per cubic meter or 0.9997 grams per cubic centimeter. Sea water with a salinity of 3.5 percent at a temperature of 10 degrees Celsius has a density of 1026.98 kilograms per cubic meter or 1.02698 grams per cubic centimeter.
No, Celsius is a temperature scale.
It would depend on the temperature of the water, or average kinetic energy. (KE) However, what you may be looking for is how much heat is needed to raise the KE, or temperature, of water. 4.184 kilojoules per gram is the heat required to raise the temperature of water 1 degree Celsius.
the temperature for hot oatmeal in Celsius is about 74 Celsius