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The general reaction for combustion of Propane is:
C3H8 + 5O2------->3CO2 + 4H2O ,
The heat evolved during the reaction is about 360kJ/mol. (120*3=360, THE HEAT OF COMBUSTION OF METHANE IS 120 KJ/MOL). Now,
Given mass=55.33 liter =55.33kg=55330g,
Molar mass=12*3+8=44g/mol, so
Number of moles=55330/44=1257.5moles, now consider,
1 mole of propane gives energy=360kj=360,000J,
1257.5 moles will give energy=E=360,000*1257.5=452700000 j , or
E=452700000/3600000 kwh=125.75kwh. For more details, contact at saqibahmad81@yahoo.com
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