A 30 gal water tank, left by itself will not use any kilowatt hours - in a month or ever!
However if it is plugged into the power system and set to maintain a specific temperature it will draw power at a rate equivalent to the heat lost to the exterior environment. This depends on the size of the tank, the insulation on the tank, the interior temperture and the exterior temperature. Considering that a hot water tank is essentially a cylinder, this is tied together by the equation:
q = 2 π k (ti - to) / ln(ro / ri)
where
q = heat transferred per unit time per unit length of cylinder or pipe (W/m, Btu/hr ft)
k = thermal conductivity of the wall(W/m.K or W/m oC, Btu/(hr oF ft2/ft))
to = temperature outside pipe or cylinder (K or oC, oF)
ti = temperature inside pipe or cylinder (K or oC, oF)
ln = the natural logarithm
ro = cylinder or pipe outside radius (m, ft)
ri = cylinder or pipe inside radius(m, ft)
A tank in active use will require more power based on the troughput of water. Each unit mass will have to be heated from its input condition to at operating temperature. Each peson in a North American home uses about 250 litres a day divided between cold and hot water.
50 watts is 0.05 kilowatts, so in 24 hours it uses 0.05 x 24 kilowatt-hours, or 1.2 kilowatt-hours of energy.
1 kilowatt hour = 3,600,000 Joules 1 Tetrajoule = 1,000,000 Joules 1 kilowatt hour = 3.6 Tetrajoules
There are 730 hours in 1 month.
Use the formula: energy = power x time If energy is in watts and time is in hours, power will be in watt-hours. Divide that by 1000 to get kWh. Alternately, you can convert watt to kilowatt before doing the multiplication - in that case, kilowatt x hours = kilowatt-hours.
Watt, kilowatt, or megawatt are units of power (energy/time). A watt is 1 joule/second. A kilowatt is a thousand joules per second. A kilowatt is also 1 kWh/hour (kilowatt-hour / hour). Since you would usually pay per kilowatt-hour, you might be more interested in the number of kilowatt-hours. A megawatt is a million joules per second - or a thousand kWh/hour.
100
1450
212
1 kilowatt = 1,000 watts 6 kilowatts = 6,000 watts 6 kilowatt-hours = 6,000 watt-hours
A 30-watt bulb uses 0.03 kilowatt-hours every hour, or 30 kilowatt-hours in 1000 hours. To find the kilowatt-hours, multiply 0.03 by the time in hours.
(3 Kw) x (5 hrs) = 15 kilowatt-hours
50 watts is 0.05 kilowatts, so in 24 hours it uses 0.05 x 24 kilowatt-hours, or 1.2 kilowatt-hours of energy.
What I think you mean, is, "How many kilowatt-hours could a 600 watt turbine produce in a month?" The answer is, not more than 432.
A standard 4 foot baseboard heat will consume 1000 watts/1Kilowatt. So if you could calculate how many hours per day/week/month you can multiply the hours by power consumption and getKWh(Kilowatt Hours) per month.
The average yearly electrical consumption around the world for those areas that have electricity is 3,500 kilowatt hours. In the United States the average is almost 11,000 kilowatt hours.
This is a trick question. You need to know the amount of water & the temperature.
Watts does not have a time component to it; so you should have asked, "How many kilowatt-hours does an oven use per hour?' For example, if the oven uses 1600 watts, then in one hour, it would use 1600 watt-hours, or 1.6 kilowatt-hours.