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What are the abbreviations of weight?
LBS. -- pounds. r oz.-- ounces.
How much in pounds is 79 oz of R-22 freon?
4.9375 lbs4.9375 lbs
How much R-134 do you add to a 1999 Dodge Caravan?
* Without Rear A/C =.96 kg (34 oz. or 2.13 lbs.) * With Rear A/C = 1.31 kg (46 oz. or 2.88 lbs.)
P x r equals 176. what is the inverse?
One inverse is 176/r = P
How many times can 46 go into 176?
It goes 3 times.
How many pounds r in 3.5 tons?
7000 lbs
What type of air conditioning fluid 2004 Ford Freestar?
The label under the hood recommends, Freon R - 134a. The quantity should be, 2 lbs 4 oz for the front A/C only system, but 3 lbs 5 oz required for the dual A/C system ( front and rear A/C )
How many pounds of refrigerant are in a Ford Focus?
1lb 8 oz of R- 134a
How much freon to fill 2004 Ford Freestar 3.9?
The label under the hood recommends 2 lbs 4 oz of R-134a if you have A/C on the front only, but 3 lbs 5 oz are recommended if you have A/C on the front and rear as well. These values are for the 2004 Ford Freestar 4.2 liter engine, very likely this is the same for the 3.9 as well.
How many. Ml r in a 5 ounces?
147.86764781 assuming they are U.S. fluid oz
How much freon does it take for 2002 Chevy Trailblazer?
How many things have been how many Saints of freon does it take to fill up a 2002 Chevrolet truck
How many 176 Ω resistors in parallel are required to carry 5 A on a 220 V line?
To find the number of 176 Ω resistors needed in parallel to carry 5 A on a 220 V line, first calculate the equivalent resistance (R) using Ohm's law: ( R = V/I = 220 V / 5 A = 44 Ω ). For resistors in parallel, the formula is ( 1/R_{eq} = 1/R_1 + 1/R_2 + ... + 1/R_n ). For n resistors of 176 Ω, this becomes ( 1/R_{eq} = n / 176 ). Setting ( R_{eq} = 44 Ω ) gives ( n = 176/44 = 4 ). Therefore, 4 resistors are required.
