60 liters
Added note
to deal with the so called 'dilution contraction' of total volume
If it were % by MASS ( %m/m), it's quite easy to do (based on the 'Mass Conservation Law). You calculate with mass (kg) and mass-% (%m/m) i.s.o. volume (L) and vol% (%v/v).
However if the meaning was: % by Volume ( %v/v) then calculation appears to become quite complicated, but not impossible if you know at least the density values of all solutions (original 10%v/v or 70%v/v and final 40%v/v).
DO NOT use: (orig. volume) + (added volume) = final volume, as done above, if exact figures are necessary.
It's only a rule of thump, an approximation. This is because fluids can contract on mixing at dilution. There is no rule such as: conservation of volume.
Your case: 60 L + 60 L (is not equal but) < 120 L final solution.
210Type your answer here...
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
4 ounces
10
Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters
210Type your answer here...
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.
4 ounces
16%
10
Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters
80 liters
That all depends on what you want the final concentration of alcohol to be.
88 ml
0.1125% of polymer solution.