Best Answer

60 liters

Added note

to deal with the so called 'dilution contraction' of total volume

If it were % by MASS ( %m/m), it's quite easy to do (based on the 'Mass Conservation Law). You calculate with mass (kg) and mass-% (%m/m) i.s.o. volume (L) and vol% (%v/v).

However if the meaning was: % by Volume ( %v/v) then calculation appears to become quite complicated, but not impossible if you know at least the density values of all solutions (original 10%v/v or 70%v/v and final 40%v/v).

DO NOT use: (orig. volume) + (added volume) = final volume, as done above, if exact figures are necessary.

It's only a rule of thump, an approximation. This is because fluids can contract on mixing at dilution. There is no rule such as: conservation of volume.

Your case: 60 L + 60 L (is not equal but) < 120 L final solution.

Q: How many liters of a 10 percent alcohol solution must be mixed with 60 liters of a 70 percent solution to get a 40 percent solution?

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Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.

4 ounces

10

Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters

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mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture

A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).

Mixing 80 liters of 15% solution and 520 liters of 90% solution will give 600 liters of 80% solution.

4 ounces

16%

10

Let L be the liters to be added. Then (L) x (0.2) + (40 x 0.9) = (L + 40) x 0.6 0.2L + 36 = 0.6L + 24 36 - 24 = (0.6 - 0.2)L 12 = 0.4L L = 12/0.4 = 120/4 = 30 Liters

80 liters

That all depends on what you want the final concentration of alcohol to be.

88 ml

0.1125% of polymer solution.