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How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
What fraction of 10 percent alcohol should be mixed with 70 percent alcohol to obtain 50 percent alcohol?
2/3 of 70% and 1/3 of 10%
How do you make 72.125 percent as a mixed number percentage?
72 and 1/8%
How do you write a mixed number or fraction as a percent?
For a fraction, divide the numerator by the denominator and multiply by 100 for a percentage. If it's a mixed number, you first have to convert it to an improper fraction then do the same thing as for a fraction.
How do you convert a mixed number to a percent?
ultiply the resulting answer by 100 to get the percent.
How many ounces of a ten percent alcohol solution must be mixed with 6 ounces of a fifteen percent alcohol solution to make a thirteen percent alcohol solution?
4 ounces
How many liters of 10 percent alcohol solution must be mixed with 70 liters of a 70 percent solution to get a 30 percent solution?
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How many liters of a 50 percent alcohol solution must be mixed with 40 liters of a 90 percent solution to get a 60 percent solution?
mary mixed 2l of an 80% acid solution with 6l of a 20% acid solution. what was the percent of acid in the resulting mixture
How many ounces of a 25 percent alcohol solution must be mixed with 9 ounces of a 30 percent alcohol solution to make a 28 percent alcohol solution?
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
What is a good homemade vinyl record cleaning solution?
Try a little denatured alcohol mixed with distilled water. Try a 25 percent alcohol / 75 percent water mixture.
How many ounces of 15 percent percent alcohol must be mixed with 23 percent alcohol solution to make 100 ounces?
Let x be the ounces of 15% alcohol solution. The amount of alcohol in the 15% solution is 0.15x, and the amount of alcohol in the 23% solution is 0.23(100 - x). Setting up the equation 0.15x + 0.23(100 - x) = 0.15(100) solves for x, which is approximately 38.5 ounces of the 15% alcohol solution needed.
How many ounces of the 50 percent alcohol solution should be mixed with the 1 percent alcohol solution to make 8 oz of the 20 percent alcohol solution?
Let x = ounces of 50% solution, and y = ounces of 1% solution. So that we have: 0.5x + 0.01y = 8(0.2) which is a linear equation in two variables, meaning there are infinitely many choices of mixing those solutions.
A pharmacist needs to obtain a 70 percent alcohol solution How many ounces of a 30 percent alcohol solution must be mixed with 40 ounces of an 80 percent alcohol solution to obtain 70 percent alcohol?
(Note: This answer assumes that the "ounces" specified are avoirdupois or other weight ounces and that percentages are by weight; otherwise possible volume changes on dilution must by considered.) The weight of pure alcohol in each solution is the product of the percentage and the total weight of the solution. Therefore, designating the unknown weight of 30 % alcohol as w, from the problem statement 0.30w + 0.80(40) = 0.70(w + 40), or 0.30w + 32 = 0.70w + 28, or 32 - 28 = w(0.70 - 0.30) or w = 4/0.40 = 10 ounces of 30 % alcohol.
How much water should be mixed to 12ml of alcohol to obtain a 12 percent of alcohol solution?
To obtain a 12% alcohol solution, you would need to mix 12ml of alcohol with 48ml of water. This would give you a total volume of 60ml, with 12% of it being alcohol.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
How many ounces of a 35 percent alcohol solution must be mixed with 14 ounces of a 40 percent alcohol solution to make a 37 percent alcohol solution?
.35x+.40*14=0.37(x+14) .35x=.37x-5.6+5.18 .35x=.37x-.42 -.02x=.42 x=21 check 21*.35+14*.4=7.35+5.6=12.95 12.95/(14+21)=.37 so you would need 21 ounces of 0.35 mixed in with 14 ounces of 40 % to get a 37% solution of which you would have 35 ounces
What form of solution when perfume mixed in alcohol?
disgusting
