20 * 25 * 40 = 20,000 cc = 20 liters
2 litres = 2000 cm3 The cross-sectional area of the vase is 11*11 cm2 = 121 cm2 So height = 2000/121 = 16.5289 cm (to 4 dp).
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
Area = Base * Height so Base = Area/Height
You can find the height of a parallelogram given the area and base measures by working backwards from the area formula. The area of a parallelogram is found with the formula: Area = Base * Height To solve this equation for Height, we divide both sides by the base. Area / Base = (Base * Height) / Base Simplify: Area / Base = Height
If you know the total area and the height are known, you can find the base. Area=(1/2)(base)(height), so if you know the height and area you can solve for the base. So now, Base=Area/(1/2)(height)
Is 0.08m the length or width of this rectangular aquarium? Need both measurements to calculate the volume of water, unless this is a SQUARE shaped aquarium.
This question has several problems. Either you are asking for the height of the container, in which you need to give the dimensions of the base of the container, or you are asking for the weight of the water in inches, which makes no sense. Rephrase and resubmit. ■
1 liter = 1000 cubic cm The diameter = 132/pai cm Base area = pai x (132/pai) 2 The volume is = Base x height = [(132) 2 /pai] x 25 /1000 litres Then do the calculation.
2 litres = 2000 cm3 The cross-sectional area of the vase is 11*11 cm2 = 121 cm2 So height = 2000/121 = 16.5289 cm (to 4 dp).
Are you asking hydrostatic (standing still) or if the water is under pressure such as the pressure at the base of a riser based on the height of the column of water?
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
The pressure that water exerts on the walls of the dam is proportional to the depth of the water or you might say the height of the column of water from the base of the dam. The hydraulic height is the same as the depth of the water to the bottom of the dam.
Volume of the cylinder = (pi) x (radius of base)2 x (height)V = (3.1416) x (10)2 x 3 = 300(pi) = 942.4778 m3 (rounded)1 m3 = (100 x 100 x 100) cm3 = 1,000,000 cm31 liter = 1,000 cm31 m3 = (1,000,000/1,000) = 1,000 litersVolume of the cylinder = 942,477.8 liters
The height of the water is the base times the tangent (opposite over adjacent) of the 29° angle. tan 29° = 0.55431 964 x 0.55431 = 534.35 feet, which is the height of the water in the fountain.
Base and height
Area = Base * Height so Base = Area/Height
base*height