To convert moles to grams, use the molar mass of methane. Methane has a molar mass of 16 (1 carbon weighs 12 grams per mole and 4 hydrogens each weigh 1 g/mol). Then multiply the two numbers together: 23.1 mol CH4 * 16 g/mol = 369.6 g CH4.
A mole of any substance is given by Avogadro's number, and is 6.0221415 × 1023 molecules per mole. Therefore, 2.43 x 10^23 molecules is .404 moles of methane.
First divide value by avagadro constant.(6.022x10623)Then multiply answer by molar mass
3.01*10^23
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
550 g of nitrogen dioxide is equal to 11,94 moles.
To calculate the grams of dichloromethane produced, we first need to convert the mass of methane from kilograms to grams, which is 1,540 grams. Given a yield of 48.2%, we can multiply this by the yield percentage to find the actual amount of dichloromethane produced: 1,540 grams of methane x 0.482 = 742.28 grams of dichloromethane.
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
How many molecules are in 30 liters of methane (CH4) at STP
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
It represent a one molecule.CH4 stands for Methane
2344222.445
If you think to 4 moles of methane the number is 24,088563428.10e+23.
567.1 mass is the equal to 56789.0 intergram. XD
0.673 moles methane ( 6.022 X 10^23/1 mole CH4) = 4.05 X 10^23 molecules of methane
8
8
16
550 g of nitrogen dioxide is equal to 11,94 moles.