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To find the number of methane molecules in 3.20 grams, you first need to calculate the molar mass of CH4 (methane), which is 16 grams/mol. Then, divide the given mass by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules, which would be 1.206 x 10^23 molecules.
To convert moles to grams, use the molar mass of methane. Methane has a molar mass of 16 (1 carbon weighs 12 grams per mole and 4 hydrogens each weigh 1 g/mol). Then multiply the two numbers together: 23.1 mol CH4 * 16 g/mol = 369.6 g CH4.
A mole of any substance is given by Avogadro's number, and is 6.0221415 × 1023 molecules per mole. Therefore, 2.43 x 10^23 molecules is .404 moles of methane.
First divide value by avagadro constant.(6.022x10623)Then multiply answer by molar mass
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
550 g of nitrogen dioxide is equal to 11,94 moles.
A thousand times as many grams as there are kilograms.
To calculate the grams of dichloromethane produced, we first need to convert the mass of methane from kilograms to grams, which is 1,540 grams. Given a yield of 48.2%, we can multiply this by the yield percentage to find the actual amount of dichloromethane produced: 1,540 grams of methane x 0.482 = 742.28 grams of dichloromethane.