To find the number of methane molecules in 3.20 grams, you first need to calculate the molar mass of CH4 (methane), which is 16 grams/mol. Then, divide the given mass by the molar mass to get the number of moles. Finally, use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of molecules, which would be 1.206 x 10^23 molecules.
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
550 g of nitrogen dioxide is equal to 11,94 moles.
A thousand times as many grams as there are kilograms.
To calculate the grams of dichloromethane produced, we first need to convert the mass of methane from kilograms to grams, which is 1,540 grams. Given a yield of 48.2%, we can multiply this by the yield percentage to find the actual amount of dichloromethane produced: 1,540 grams of methane x 0.482 = 742.28 grams of dichloromethane.
To find the number of molecules in 10 grams of methane, you first convert the mass to moles using the molar mass of methane. The molar mass of methane is about 16 g/mol. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to molecules. So, 10 grams of methane contains approximately 3.76 x 10^23 molecules.
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
It represent a one molecule.CH4 stands for Methane
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There are approximately 4.68 x 10^22 molecules of methane in 0.123 moles of methane. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules per mole.
567.1 mass is the equal to 56789.0 intergram. XD
If you think to 4 moles of methane the number is 24,088563428.10e+23.
8
8
16
550 g of nitrogen dioxide is equal to 11,94 moles.
A thousand times as many grams as there are kilograms.