8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
If you think to 4 moles of methane the number is 24,088563428.10e+23.
550 g of nitrogen dioxide is equal to 11,94 moles.
A thousand times as many grams as there are kilograms.
To calculate the grams of dichloromethane produced, we first need to convert the mass of methane from kilograms to grams, which is 1,540 grams. Given a yield of 48.2%, we can multiply this by the yield percentage to find the actual amount of dichloromethane produced: 1,540 grams of methane x 0.482 = 742.28 grams of dichloromethane.
Find out the percentage of hydrogen in the molar mass of methane. Molar mass of CH4: C = 1 * 12.01 g = 12.01 g H = 4 * 1.01 g = 4.04 g Total = 16.05 g 4.04 g/16.05 g * 100% = 25.171% 0.25171 * 20 g = 5.0342 g There are about 5.03 grams of hydrogen in 20 grams of methane gas.
8 grams. Or more exactly, in 30.0 grams of methane there is 7.54 grams of hydrogen.
2344222.445
It represent a one molecule.CH4 stands for Methane
There are approximately 4.68 x 10^22 molecules of methane in 0.123 moles of methane. This is calculated using Avogadro's number, which is 6.022 x 10^23 molecules per mole.
567.1 mass is the equal to 56789.0 intergram. XD
If you think to 4 moles of methane the number is 24,088563428.10e+23.
550 g of nitrogen dioxide is equal to 11,94 moles.
8
8
16
A thousand times as many grams as there are kilograms.