2000*60=120 000
as 2000 is taken to have only one significant figure, we have a result of 100 000
Two significant figures.
There are three significant figures in 2.07 hours. The numbers 2, 0, and 7 are all considered significant in this case.
3 of them.
How many significant figures are in 20.8
There are 3 significant figures in 94.2.
10.071428571 hours. or 10 hours 4 minutes (approx). Not as precise as the first answer, but then it is unlikely that the distance or speed were measured to an accuracy of 11 significant figures!
3 significant figures.
4487 has four significant figures.
101330 has 6 significant figures.
There are four significant figures in 0.005120.
0.0375 has three significant figures.
There are four significant figures in 0.1111.