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We assume that the quantity 56.22 is in grams. The formula mass of CF2Cl2 is 12.0 + 2(19.0) + 2(35.5) = 121.0Amount of CF2Cl2 = mass of pure sample/molar mass = 56.22/121.0 = 0.465mol There are 0.465 moles of CF2Cl2 in a 56.22 pure sample.
1.64×1022 molecules
1.51 x 10 ^23 molecules
2.05×1022 molecules
The number of molecules is 6,3985.10e24.
We assume that the quantity 56.22 is in grams. The formula mass of CF2Cl2 is 12.0 + 2(19.0) + 2(35.5) = 121.0Amount of CF2Cl2 = mass of pure sample/molar mass = 56.22/121.0 = 0.465mol There are 0.465 moles of CF2Cl2 in a 56.22 pure sample.
1.64×1022 molecules
10kg
5745 minutes ÷ 60 minutes/hour = 95.75 hours (95 hours and 45 minutes)
The number of molecules is 6,3985.10e24.
The number of water molecules is 16,728.10e23.
2.05×1022 molecules
1.51 x 10 ^23 molecules
The answer is 1,357.10 ex.23 molecules.
The answer is 1,357.10 ex.23 molecules.
.1764
1.27X10^22