To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.
258,000 g
1470 g
2000 g
-1 * * * * * Actually, it is +1
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
620 grams mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg
2
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
0,34 g HCl contain 5,6.10e21 molecules.
The answer is 1,357.10 ex.23 molecules.
There are around 19.4*1023 molecules in 155.25 g of ozone. Its molecular weight is 48.
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules