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To determine the number of molecules in 15.9 g of IF7 (iodine heptafluoride), first calculate the molar mass of IF7. The molar mass is approximately 144.9 g/mol. Next, use the formula: number of moles = mass (g) / molar mass (g/mol). Thus, ( \text{number of moles} = \frac{15.9 , \text{g}}{144.9 , \text{g/mol}} \approx 0.1096 , \text{mol} ). Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) molecules/mol) to find the number of molecules: (0.1096 , \text{mol} \times 6.022 \times 10^{23} \approx 6.60 \times 10^{22}) molecules of IF7.

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What is the number of molecules in 9.0 g of steam and how?

To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.


How many grams are in 8.2 x 1022 molecules f N2l6?

To find the mass in grams of 8.2 x 10^22 molecules of N2l6, we first need to determine the molar mass of N2l6. The molar mass is calculated by adding the atomic masses of nitrogen (N) and iodine (l) in the formula. N has an atomic mass of approximately 14 g/mol and I has about 127 g/mol; thus, N2l6 has a molar mass of (2 * 14) + (6 * 127) = 868 g/mol. Next, we convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol): 8.2 x 10^22 molecules * (1 mol / 6.022 x 10^23 molecules) ≈ 0.136 moles. Finally, we multiply the number of moles by the molar mass: 0.136 moles * 868 g/mol ≈ 118.5 grams. Therefore, there are approximately 118.5 grams of N2l6 in 8.2 x 10^22 molecules.


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Sephadex G-100 has a pore size that typically ranges from 40 to 100 nanometers. This makes it suitable for the separation of molecules such as proteins and polysaccharides, allowing larger molecules to elute first while smaller molecules are retained within the gel matrix. It is commonly used in size exclusion chromatography for the purification and analysis of biomolecules.


How many g are in 1.47kg?

1470 g


How many g for 2kg?

2000 g