To find the number of molecules in 9.0 g of steam (water vapor), first determine the number of moles. The molar mass of water (H₂O) is approximately 18.02 g/mol. Therefore, 9.0 g of steam is equivalent to ( \frac{9.0 \text{ g}}{18.02 \text{ g/mol}} \approx 0.5 ) moles. Since one mole contains Avogadro's number of molecules ((6.022 \times 10^{23}) molecules/mol), the total number of molecules is (0.5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} \approx 3.01 \times 10^{23} ) molecules.
To find the mass in grams of 8.2 x 10^22 molecules of N2l6, we first need to determine the molar mass of N2l6. The molar mass is calculated by adding the atomic masses of nitrogen (N) and iodine (l) in the formula. N has an atomic mass of approximately 14 g/mol and I has about 127 g/mol; thus, N2l6 has a molar mass of (2 * 14) + (6 * 127) = 868 g/mol. Next, we convert the number of molecules to moles using Avogadro's number (6.022 x 10^23 molecules/mol): 8.2 x 10^22 molecules * (1 mol / 6.022 x 10^23 molecules) ≈ 0.136 moles. Finally, we multiply the number of moles by the molar mass: 0.136 moles * 868 g/mol ≈ 118.5 grams. Therefore, there are approximately 118.5 grams of N2l6 in 8.2 x 10^22 molecules.
258,000 g
1470 g
2000 g
22.0 g of silver chloride contain 0,918.10e23 molecules.
26.3 g of calcium hydroxide contain 2,054 molecules.
32 g SO2 x 1 mole SO2/96 g x 6.02x10^23 molecules/mole = 2.0x10^23 molecules
620 grams mercury (1 mole Hg/200.6 grams) = 3.09 moles Hg
2
The answer is 1,57.10e27 molecules.
1,4.10e23 molecules
There are 3.34 x 10^22 molecules of H2O in 1.0 g of water.
0,34 g HCl contain 5,6.10e21 molecules.
The answer is 1,357.10 ex.23 molecules.
There are around 19.4*1023 molecules in 155.25 g of ozone. Its molecular weight is 48.
(6.022*10^23) * [1.000 (g) / (8 * 32.00 (g/mol)] = 2.352*10^21 molecules