The reaction of carbon dioxide and potassium oxide is 4KO2 + 2CO2 = 2K2CO3 + 3O2. 156 grams of CO2 is 3.54 moles, which will produce 5.31 moles of O2.
6 moles
The reaction is:WO3 + 3 H2 = W + 3 H2OThree moles of hydrogen for one mole of wolfram.
0,044 moles of NH3 can be produced.
8 mol
Balanced equation. CH4 + 2O2 -> CO2 + 2H2O one to one, but set-up anyway and limiting reacting known 2.0 moles CH4 (1 mole CO2/1 mole CH4) = 2.0 moles CO2 produced ( by the way, those numbers are subscripts, not superscripts )
6 moles
None, unless there is metallic potassium in the reaction mixture. Assuming excess potassium metal is present then 14 moles of KBr can be produced. 7BaBr2 + excess potassium -----> 14KBr + 7 Ba
The reaction is:WO3 + 3 H2 = W + 3 H2OThree moles of hydrogen for one mole of wolfram.
0,044 moles of NH3 can be produced.
8,038 moles of ammonia were produced.
N2 + 3H2 --> 2NH3 You have been told, indirectly, that nitrogen limits and will drive the reaction. 3 moles N2 (2 moles NH3/1 mole N2) = 6 moles ammonia gas produced ========================
X = 0.489 moles of AgCl produced
30 moles
4 moles
4 moles
30 moles
The answer is 30 moles.